Palindrome Pairs – Leetcode Challenge – Java Solution
This is the java solution for the Leetcode problem – Palindrome Pairs – Leetcode Challenge – Java Solution.
Source – qiyuangong’s repository.
class Solution { //https://leetcode.com/problems/palindrome-pairs/discuss/79195/O(n-*-k2)-java-solution-with-Trie-structure private static class TrieNode { TrieNode[] next; int index; Listlist; TrieNode() { next = new TrieNode[26]; index = -1; list = new ArrayList<>(); } } public List > palindromePairs(String[] words) { List
> res = new ArrayList<>(); TrieNode root = new TrieNode(); for (int i = 0; i < words.length; i++) { addWord(root, words[i], i); } for (int i = 0; i < words.length; i++) { search(words, i, root, res); } return res; } private void addWord(TrieNode root, String word, int index) { for (int i = word.length() - 1; i >= 0; i--) { int j = word.charAt(i) - 'a'; if (root.next[j] == null) { root.next[j] = new TrieNode(); } if (isPalindrome(word, 0, i)) { root.list.add(index); } root = root.next[j]; } root.list.add(index); root.index = index; } private void search(String[] words, int i, TrieNode root, List
> res) { for (int j = 0; j < words[i].length(); j++) { if (root.index >= 0 && root.index != i && isPalindrome(words[i], j, words[i].length() - 1)) { res.add(Arrays.asList(i, root.index)); } root = root.next[words[i].charAt(j) - 'a']; if (root == null) return; } for (int j : root.list) { if (i == j) continue; res.add(Arrays.asList(i, j)); } } private boolean isPalindrome(String word, int i, int j) { while (i < j) { if (word.charAt(i++) != word.charAt(j--)) return false; } return true; } }