Rank sort a list of dictionaries based on a value in Python
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[{'name_html': 's', 'mkc': 1, 'kills': 14, 'deaths': 4, 'lastCharacter': 'Spaz', 'lastName': 's', 'games': 3, 'scores': 439, 'aid': 'pb - IF4JVRcuLA == '}, {'name_html': 'Android48457626', 'mkc': 0, 'kills': 0, 'deaths': 6, 'lastCharacter': 'Kronk', 'lastName': 'peo', 'games': 3, 'scores': 205, 'aid': 'pb - IF4rVWseCg == '}]Let’s take the list of dictionaries above as an example. I’d like to sort this list based on the scores value. To do this we can use the sorted() function
rank sort list dictionariesrank_sorted = sorted(res, key=lambda x: x['scores'])
print(rank_sorted)
#[{'name_html': 'Android48457626', 'mkc': 0, 'kills': 0, 'deaths': 6, 'lastCharacter': 'Kronk', 'lastName': 'peo', 'games': 3, 'scores': 205, 'aid': 'pb - IF4rVWseCg == '}, {'name_html': 's', 'mkc': 1, 'kills': 14, 'deaths': 4, 'lastCharacter': 'Spaz', 'lastName': 's', 'games': 3, 'scores': 439, 'aid': 'pb - IF4JVRcuLA == '}]This is how I did it.
